Calculatorism

First-Order Half-Life Calculator

Enter the first-order rate constant k; using t½ = ln2 / k the tool instantly computes the half-life — the time required for the reactant concentration to halve.

Input Data

Rate Constant
1/s

Results

10.0021s

At a glance:The half-life (symbol t½) is the time required for the reactant concentration (or amount of radioactive substance) to fall to half of its original value; it is an intuitive measure of how fast a reaction proceeds. For a 'first-order reaction' — one whose rate is proportional to the first power of a single reactant concentration, rate = k[A] — the half-life has a very special and important property: it is a constant, completely independent of the initial reactant concentration. The formula is t½ = ln2 / k ≈ 0.693 / k, where k is the first-order rate constant (unit 1/time, most commonly 1/s). It derives from the first-order integrated rate law ln([A]₀/[A]) = kt: when [A] = [A]₀/2 (exactly half remains), ln(2) = k·t½, which rearranges to t½ = ln2/k. The reason 'constant half-life' is the hallmark of first-order reactions is that no matter what concentration you start from, after each t½ the concentration halves again: after 1 half-life 1/2 remains, after 2 half-lives 1/4, after 3 half-lives 1/8 …, and after n half-lives (1/2)ⁿ remains. Using this tool's default: k = 0.0693 /s, so t½ = 0.693 / 0.0693 ≈ 10 s, meaning every 10 s the reactant concentration is halved. This property — 'the half-life does not change with the initial amount' — is exactly the scientific basis of radioactive isotope dating (e.g. carbon-14 dating): radioactive decay is always a first-order process, and every isotope has a fixed half-life (carbon-14 ≈ 5730 years, iodine-131 ≈ 8 days, uranium-238 ≈ 4.5 billion years). By measuring the remaining amount against the known half-life, scientists work back to the sample's age. The half-life is inversely proportional to the rate constant k: a larger k (faster reaction) gives a shorter half-life; a smaller k (slower reaction) gives a longer one. It must be emphasised that 'half-life independent of initial concentration' holds only for first-order reactions. For a zero-order reaction t½ = [A]₀/(2k), proportional to the initial concentration; for a second-order reaction t½ = 1/(k[A]₀), inversely proportional to it. Thus, if an experiment shows a reaction's half-life does not change with starting concentration, that is strong evidence it is first-order. Half-life has very broad applications: (1) radioactive dating and nuclear medicine (clearance of radioactive drugs, radiotherapy dose planning); (2) pharmacokinetics — most drugs are metabolised by an approximately first-order process, and the half-life determines dosing intervals (after about 4–5 half-lives the drug is essentially cleared); (3) assessing degradation rates of chemicals in the environment; (4) estimating shelf life of food and reagents. Using this calculator: first, k must be the first-order rate constant, unit 1/time (e.g. 1/s, 1/min, 1/year), and the half-life unit corresponds to k's time unit (k in 1/s → t½ in seconds). Second, k must be greater than 0, otherwise the reaction does not proceed and the half-life is undefined (this tool returns 0). Third, this formula applies only to first-order reactions; for zero- and second-order reactions use the corresponding formulas. Fourth, ln2 ≈ 0.6931 is the natural logarithm of 2, not to be confused with log₁₀2 ≈ 0.301. In short, this calculator lets you quickly find the constant half-life from the first-order rate constant — a core tool for chemical kinetics and radioactive-decay study.

Formula

First-order half-life: t½ = ln2 / k ≈ 0.693 / k.

Source (integrated rate law): ln([A]₀/[A]) = kt, substitute [A] = [A]₀/2.

Remaining amount: after n half-lives, concentration is (1/2)ⁿ.

Reverse (k from half-life): k = ln2 / t½.

$$t_{1/2} = \dfrac{\ln 2}{k} \approx \dfrac{0.693}{k}$$

How to Use

  1. Enter the first-order rate constant k (unit 1/s), must be greater than 0.
  2. The right panel instantly shows the half-life t½ (seconds), the time for the concentration to halve.
  3. If k uses another time unit (1/min, 1/year), the resulting t½ unit is correspondingly minutes or years.

First-order rate constant k vs half-life t½

First-order rate constant k vs half-life t½
Rate Constant k (1/s)Half-Life t½ (s)Reaction Speed
0.69311.00Very fast
0.069310.00Moderate
0.010069.31Slower
0.0050138.63Slow

Half-life is inversely proportional to k: a larger k means a faster reaction and a shorter half-life, and this half-life does not change with initial concentration.

Case Studies

Half-life from a rate constant

A first-order reaction has rate constant k = 0.0693 /s; find its half-life.

t½ = ln2 / k = 0.6931 / 0.0693 ≈ 10.0 s.

Meaning every 10 s the reactant concentration halves; after 20 s 1/4 remains, after 30 s 1/8, regardless of the starting concentration.

Decay constant of a radioactive isotope

Iodine-131 has a half-life of about 8 days; reverse its decay constant k = ln2 / t½ = 0.693 / 8 ≈ 0.0866 /day.

Because radioactive decay is first-order with a fixed half-life, iodine-131's dose and clearance time in nuclear medicine can be precisely predicted.

After about 5 half-lives (40 days) the residual amount falls to about 3%, close to cleared.

FAQ

Why is the first-order half-life independent of initial concentration?

Because in the first-order integrated rate law ln([A]₀/[A]) = kt, when the concentration halves [A]₀/[A] = 2; taking the logarithm gives ln2 = k·t½, so t½ = ln2/k contains no initial concentration [A]₀. This is unique to first-order reactions and is the basis of radioactive dating.

Is the zero- and second-order half-life also constant?

No. Zero-order: t½ = [A]₀/(2k), proportional to the initial concentration; second-order: t½ = 1/(k[A]₀), inversely proportional to it. Only the first-order half-life is constant, so whether the half-life changes with concentration can be used to judge the reaction order.

What is ln2, and could it be confused with log2?

ln2 is the natural logarithm of 2, approximately 0.6931, and that is what the formula uses. Do not mistake it for the common logarithm log₁₀2 ≈ 0.301, otherwise the result will be off by a conversion factor and be completely wrong.

How is the half-life unit determined?

The half-life unit is set by the time unit of the rate constant k. k in 1/s → seconds; k in 1/min → minutes; k in 1/year → years. This calculator defaults to 1/s and outputs seconds.

After how many half-lives is the reactant essentially consumed?

The rule of thumb is about 5 half-lives: the remaining amount is then (1/2)⁵ ≈ 3.1%, generally treated as essentially cleared. This is often cited in pharmacokinetics (judging complete drug metabolism) and radiation protection.

Related Tools

References

Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.

Found a problem with the results?

If this calculator's result is wrong, or you have any question about the calculation logic, please let us know. You are viewing:First-Order Half-Life Calculator(/chemistry/first-order-half-life)。