Gibbs Free Energy Calculator
Enter the enthalpy change ΔH, absolute temperature T and entropy change ΔS; using ΔG = ΔH − TΔS the tool instantly computes the Gibbs free-energy change and judges whether the reaction is spontaneous at that temperature.
Input Data
Results
At a glance:Gibbs free energy (symbol G) is the core criterion in thermodynamics for judging 'whether a chemical reaction or physical process will proceed spontaneously at constant temperature and pressure', proposed by the American scientist J. W. Gibbs. In practice we care about the free-energy change ΔG before and after the reaction, defined by ΔG = ΔH − T·ΔS, where ΔH is the enthalpy change (reflecting heat release/absorption, unit kJ/mol), T is the absolute temperature (Kelvin K), and ΔS is the entropy change (reflecting the change in disorder, unit J/(mol·K)). Note that ΔH and ΔS use different units (one kJ, one J), so before calculating ΔS must be converted to kJ/(mol·K) (divide by 1000); this calculator does that automatically. The sign of ΔG directly tells us the spontaneous direction: when ΔG < 0 the reaction is spontaneous at that temperature (exergonic, proceeds forward); when ΔG = 0 the system is at equilibrium with equal forward and reverse rates; when ΔG > 0 the forward reaction is non-spontaneous (requires external energy input), and the reverse is spontaneous. This formula captures the essence of the second law of thermodynamics: whether a process is spontaneous depends on the competition between the 'energy factor (ΔH)' and the 'disorder factor (TΔS)'. Exothermic reactions (ΔH < 0) and entropy-increasing reactions (ΔS > 0) both favour spontaneity (making ΔG smaller); endothermic (ΔH > 0) and entropy-decreasing (ΔS < 0) reactions disfavour it. In particular, temperature T is the weight of the entropy term: the higher the temperature, the greater the effect of the entropy change on ΔG. Using this tool's default (approximate combustion of hydrogen to liquid water): ΔH = −285.8 kJ/mol (strongly exothermic), ΔS = −163.2 J/(mol·K) (gas to liquid, entropy decreases), at T = 298 K (25°C), ΔG = −285.8 − 298 × (−0.1632) = −285.8 + 48.63 ≈ −237.2 kJ/mol < 0, so the reaction is highly spontaneous at room temperature. From the four combinations of ΔH, ΔS signs we can judge how spontaneity varies with temperature: (1) ΔH<0, ΔS>0: spontaneous at any temperature (ΔG always negative); (2) ΔH>0, ΔS<0: non-spontaneous at any temperature; (3) ΔH<0, ΔS<0: spontaneous at low temperature, non-spontaneous at high (e.g. freezing, exothermic polymerisation); (4) ΔH>0, ΔS>0: spontaneous at high temperature, non-spontaneous at low (e.g. ice melting, most decomposition reactions). For the last two there is a 'transition temperature' T = ΔH/ΔS (where ΔG = 0), past which the spontaneous direction reverses. Gibbs free energy has very broad uses: judging reaction feasibility, predicting direction, computing equilibrium constants from ΔG° (ΔG° = −RT ln K), linking cell potential in electrochemistry via ΔG = −nFE, and analysing spontaneity of phase changes and dissolution. When using it note: first, convert temperature to Kelvin. Second, do not mix the units of ΔH and ΔS (kJ vs J) — this calculator handles the conversion. Third, ΔG < 0 only means 'thermodynamically possibly spontaneous', not necessarily fast — reaction rate is set by activation energy and kinetics, a different level (e.g. diamond turning to graphite has ΔG<0 yet is extremely slow). In short, this calculator lets you quickly find ΔG from ΔH, T, ΔS and judge spontaneity — an indispensable tool in chemical thermodynamics.
Formula
Gibbs free-energy change: ΔG = ΔH − T · ΔS.
Unit: convert ΔS from J/(mol·K) to kJ/(mol·K) by dividing by 1000 before substituting.
Spontaneity: ΔG < 0 spontaneous, ΔG = 0 equilibrium, ΔG > 0 non-spontaneous.
Transition temperature (ΔG = 0): T = ΔH ÷ ΔS.
$$\Delta G = \Delta H - T\,\Delta S$$How to Use
- Enter the reaction enthalpy change ΔH (kJ/mol, negative for exothermic).
- Enter the absolute temperature T (Kelvin, 25°C = 298 K) and entropy change ΔS (J/(mol·K)).
- The right panel instantly shows ΔG (kJ/mol); a negative value means the reaction is spontaneous.
Effect of ΔH and ΔS sign combinations on reaction spontaneity
| ΔH | ΔS | Low Temp | High Temp | Note |
|---|---|---|---|---|
| Negative | Positive | Spontaneous | Spontaneous | Spontaneous at any temp (ΔG always negative) |
| Negative | Negative | Spontaneous | Non-spontaneous | Spontaneous at low temp, e.g. freezing |
| Positive | Positive | Non-spontaneous | Spontaneous | Spontaneous at high temp, e.g. decomposition, melting |
| Positive | Negative | Non-spontaneous | Non-spontaneous | Non-spontaneous at any temp |
The last two columns imply a transition temperature T = ΔH/ΔS; crossing it reverses the spontaneous direction.
Case Studies
Combustion of hydrogen to liquid water
Reaction ΔH = −285.8 kJ/mol (strongly exothermic), ΔS = −163.2 J/(mol·K) (gas to liquid, entropy decreases); find ΔG at 25°C (298 K).
ΔG = −285.8 − 298 × (−0.1632) = −285.8 + 48.63 ≈ −237.2 kJ/mol.
ΔG < 0, highly spontaneous at room temperature — the thermodynamic basis for hydrogen–oxygen fuel cells doing work.
Transition temperature of calcium carbonate decomposition
CaCO₃ → CaO + CO₂ is endothermic (ΔH > 0) and entropy-increasing (ΔS > 0), a 'high-temperature spontaneous' type.
At low temperature TΔS is smaller than ΔH, ΔG > 0, not spontaneous; as temperature rises TΔS grows and ΔG turns negative.
Transition temperature T = ΔH/ΔS; only above it does decomposition become spontaneous, explaining why limestone needs high-temperature calcination to become quicklime.
FAQ
If ΔG is negative, does the reaction definitely happen?
ΔG < 0 only means the reaction is thermodynamically 'possibly spontaneous'; it does not guarantee a fast reaction. The rate is set by activation energy and kinetics, which is a different matter from spontaneity. For example diamond → graphite has ΔG < 0 but is extremely slow and not observed at room temperature.
ΔH and ΔS have different units — how to handle?
ΔH is usually kJ/mol, ΔS is J/(mol·K); before computing ΔG they must be unified. Divide ΔS by 1000 to convert to kJ/(mol·K), then substitute into ΔG = ΔH − TΔS. This calculator does the conversion automatically, so you can enter the original units directly.
What is the transition temperature?
When ΔH and ΔS have the same sign there is a temperature making ΔG = 0, namely T = ΔH/ΔS. Below (or above) this temperature the reaction is spontaneous; crossing it reverses the direction. For example ice melting reaches ΔG = 0 at 0°C (273 K), its transition temperature.
Why must temperature be in Kelvin?
Because the T in ΔG = ΔH − TΔS is the absolute temperature, reflecting the absolute scale of molecular thermal motion starting from absolute zero. Using Celsius makes the TΔS term wrong or even negative, leading to a completely wrong spontaneity judgement. Always use K = °C + 273.15.
Is ΔG related to the equilibrium constant K?
Yes. The relation between standard Gibbs free-energy change and equilibrium constant is ΔG° = −RT ln K. The more negative ΔG°, the larger K, meaning the reaction more favours products. This lets us predict the extent of a reaction from thermodynamic data, not just its direction.
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References
Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.