Calculatorism

Gibbs Free Energy Calculator

Enter the enthalpy change ΔH, absolute temperature T and entropy change ΔS; using ΔG = ΔH − TΔS the tool instantly computes the Gibbs free-energy change and judges whether the reaction is spontaneous at that temperature.

Input Data

Enthalpy
kJ/mol
Temperature
K
Entropy
J/(mol·K)

Results

-237.1664kJ/mol

At a glance:Gibbs free energy (symbol G) is the core criterion in thermodynamics for judging 'whether a chemical reaction or physical process will proceed spontaneously at constant temperature and pressure', proposed by the American scientist J. W. Gibbs. In practice we care about the free-energy change ΔG before and after the reaction, defined by ΔG = ΔH − T·ΔS, where ΔH is the enthalpy change (reflecting heat release/absorption, unit kJ/mol), T is the absolute temperature (Kelvin K), and ΔS is the entropy change (reflecting the change in disorder, unit J/(mol·K)). Note that ΔH and ΔS use different units (one kJ, one J), so before calculating ΔS must be converted to kJ/(mol·K) (divide by 1000); this calculator does that automatically. The sign of ΔG directly tells us the spontaneous direction: when ΔG < 0 the reaction is spontaneous at that temperature (exergonic, proceeds forward); when ΔG = 0 the system is at equilibrium with equal forward and reverse rates; when ΔG > 0 the forward reaction is non-spontaneous (requires external energy input), and the reverse is spontaneous. This formula captures the essence of the second law of thermodynamics: whether a process is spontaneous depends on the competition between the 'energy factor (ΔH)' and the 'disorder factor (TΔS)'. Exothermic reactions (ΔH < 0) and entropy-increasing reactions (ΔS > 0) both favour spontaneity (making ΔG smaller); endothermic (ΔH > 0) and entropy-decreasing (ΔS < 0) reactions disfavour it. In particular, temperature T is the weight of the entropy term: the higher the temperature, the greater the effect of the entropy change on ΔG. Using this tool's default (approximate combustion of hydrogen to liquid water): ΔH = −285.8 kJ/mol (strongly exothermic), ΔS = −163.2 J/(mol·K) (gas to liquid, entropy decreases), at T = 298 K (25°C), ΔG = −285.8 − 298 × (−0.1632) = −285.8 + 48.63 ≈ −237.2 kJ/mol < 0, so the reaction is highly spontaneous at room temperature. From the four combinations of ΔH, ΔS signs we can judge how spontaneity varies with temperature: (1) ΔH<0, ΔS>0: spontaneous at any temperature (ΔG always negative); (2) ΔH>0, ΔS<0: non-spontaneous at any temperature; (3) ΔH<0, ΔS<0: spontaneous at low temperature, non-spontaneous at high (e.g. freezing, exothermic polymerisation); (4) ΔH>0, ΔS>0: spontaneous at high temperature, non-spontaneous at low (e.g. ice melting, most decomposition reactions). For the last two there is a 'transition temperature' T = ΔH/ΔS (where ΔG = 0), past which the spontaneous direction reverses. Gibbs free energy has very broad uses: judging reaction feasibility, predicting direction, computing equilibrium constants from ΔG° (ΔG° = −RT ln K), linking cell potential in electrochemistry via ΔG = −nFE, and analysing spontaneity of phase changes and dissolution. When using it note: first, convert temperature to Kelvin. Second, do not mix the units of ΔH and ΔS (kJ vs J) — this calculator handles the conversion. Third, ΔG < 0 only means 'thermodynamically possibly spontaneous', not necessarily fast — reaction rate is set by activation energy and kinetics, a different level (e.g. diamond turning to graphite has ΔG<0 yet is extremely slow). In short, this calculator lets you quickly find ΔG from ΔH, T, ΔS and judge spontaneity — an indispensable tool in chemical thermodynamics.

Formula

Gibbs free-energy change: ΔG = ΔH − T · ΔS.

Unit: convert ΔS from J/(mol·K) to kJ/(mol·K) by dividing by 1000 before substituting.

Spontaneity: ΔG < 0 spontaneous, ΔG = 0 equilibrium, ΔG > 0 non-spontaneous.

Transition temperature (ΔG = 0): T = ΔH ÷ ΔS.

$$\Delta G = \Delta H - T\,\Delta S$$

How to Use

  1. Enter the reaction enthalpy change ΔH (kJ/mol, negative for exothermic).
  2. Enter the absolute temperature T (Kelvin, 25°C = 298 K) and entropy change ΔS (J/(mol·K)).
  3. The right panel instantly shows ΔG (kJ/mol); a negative value means the reaction is spontaneous.

Effect of ΔH and ΔS sign combinations on reaction spontaneity

Effect of ΔH and ΔS sign combinations on reaction spontaneity
ΔHΔSLow TempHigh TempNote
NegativePositiveSpontaneousSpontaneousSpontaneous at any temp (ΔG always negative)
NegativeNegativeSpontaneousNon-spontaneousSpontaneous at low temp, e.g. freezing
PositivePositiveNon-spontaneousSpontaneousSpontaneous at high temp, e.g. decomposition, melting
PositiveNegativeNon-spontaneousNon-spontaneousNon-spontaneous at any temp

The last two columns imply a transition temperature T = ΔH/ΔS; crossing it reverses the spontaneous direction.

Case Studies

Combustion of hydrogen to liquid water

Reaction ΔH = −285.8 kJ/mol (strongly exothermic), ΔS = −163.2 J/(mol·K) (gas to liquid, entropy decreases); find ΔG at 25°C (298 K).

ΔG = −285.8 − 298 × (−0.1632) = −285.8 + 48.63 ≈ −237.2 kJ/mol.

ΔG < 0, highly spontaneous at room temperature — the thermodynamic basis for hydrogen–oxygen fuel cells doing work.

Transition temperature of calcium carbonate decomposition

CaCO₃ → CaO + CO₂ is endothermic (ΔH > 0) and entropy-increasing (ΔS > 0), a 'high-temperature spontaneous' type.

At low temperature TΔS is smaller than ΔH, ΔG > 0, not spontaneous; as temperature rises TΔS grows and ΔG turns negative.

Transition temperature T = ΔH/ΔS; only above it does decomposition become spontaneous, explaining why limestone needs high-temperature calcination to become quicklime.

FAQ

If ΔG is negative, does the reaction definitely happen?

ΔG < 0 only means the reaction is thermodynamically 'possibly spontaneous'; it does not guarantee a fast reaction. The rate is set by activation energy and kinetics, which is a different matter from spontaneity. For example diamond → graphite has ΔG < 0 but is extremely slow and not observed at room temperature.

ΔH and ΔS have different units — how to handle?

ΔH is usually kJ/mol, ΔS is J/(mol·K); before computing ΔG they must be unified. Divide ΔS by 1000 to convert to kJ/(mol·K), then substitute into ΔG = ΔH − TΔS. This calculator does the conversion automatically, so you can enter the original units directly.

What is the transition temperature?

When ΔH and ΔS have the same sign there is a temperature making ΔG = 0, namely T = ΔH/ΔS. Below (or above) this temperature the reaction is spontaneous; crossing it reverses the direction. For example ice melting reaches ΔG = 0 at 0°C (273 K), its transition temperature.

Why must temperature be in Kelvin?

Because the T in ΔG = ΔH − TΔS is the absolute temperature, reflecting the absolute scale of molecular thermal motion starting from absolute zero. Using Celsius makes the TΔS term wrong or even negative, leading to a completely wrong spontaneity judgement. Always use K = °C + 273.15.

Is ΔG related to the equilibrium constant K?

Yes. The relation between standard Gibbs free-energy change and equilibrium constant is ΔG° = −RT ln K. The more negative ΔG°, the larger K, meaning the reaction more favours products. This lets us predict the extent of a reaction from thermodynamic data, not just its direction.

Related Tools

References

Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.

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