Uniform Acceleration Calculator
Solve the five uniform-acceleration (SUVAT) equations: v=u+at, s=(u+v)t/2, s=ut+½at², v²=u²+2as, s=vt−½at². Enter any 3 of u,v,a,s,t.
Input Data
Results
At a glance:Under constant acceleration a, motion is governed by five linked 'SUVAT' equations (s displacement, u/v initial/final velocity, a acceleration, t time): v=u+at; s=(u+v)t/2; s=ut+½at²; v²=u²+2as; s=vt−½at². They apply whenever a is constant — e.g. free fall (a=g), braking with steady deceleration, or a car at fixed throttle. Properties: (1) velocity changes linearly with time (v=u+at); (2) displacement is quadratic in time; (3) the v²=u²+2as form needs no time. Example: a car brakes from u=20 m/s at a=−5 m/s²: stopping distance s=(0−20²)/(2×(−5))=40 m, time t=(0−20)/(−5)=4 s. Applications: (1) vehicle braking and stopping distance; (2) free-fall and dropped objects; (3) projectile launch (horizontal/vertical split); (4) sports — sprint, long jump; (5) DSE Physics structured questions.
Formula
v = u + a·t
s = (u+v)·t/2
s = u·t + ½·a·t²
v² = u² + 2·a·s
s = v·t − ½·a·t²
$$v = u + at, \quad s = ut + \tfrac{1}{2}at^2, \quad v^2 = u^2 + 2as$$How to Use
- Enter any three of u, v, a, s, t.
- The tool solves the remaining two via the SUVAT set.
- Common: free fall a=9.81; braking a negative.
Case Studies
Car braking
u=20 m/s, v=0, a=−5 m/s².
Stopping distance s=(0²−20²)/(2×(−5))=40 m.
Stopping time t=(0−20)/(−5)=4 s.
Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.