Calculatorism

Thermal Conductivity Calculator

Enter conductivity k, area A, temp difference ΔT and thickness L to compute heat-transfer rate, thermal resistance and heat flux. Copper k=400, A=1, ΔT=100, L=0.01 → 4 MW.

Input Data

Thermal conductivity k (W/(m·K)). Silver 429; copper 400; gold 317; aluminum 237; iron 80; glass 1; water 0.6; air 0.026.
W/(m·K)
Cross-sectional area A (m²). CPU die 1e-4; heatsink 0.01; window 1; wall 10.
m²
Temperature difference ΔT (K or °C). CPU 50; indoor-outdoor 10; industrial 100–1000.
K
Thickness L (m). Die 0.001; heatsink 0.01; glass 0.005; wall 0.2; foam 0.1.
m

Results

Heat-transfer rate Q/t (W).
4,000,000W
Thermal resistance R = L/(kA) (K/W).
0.000025K/W
Heat flux q = Q/A (W/m²).
4,000,000W/m²

At a glance:Fourier's law of heat conduction (Joseph Fourier, 1822, 'The Analytical Theory of Heat'): when a temperature difference is maintained across a material, the heat per unit time is Q/t=k·A·ΔT/L. k is thermal conductivity (W/(m·K), the material's ability to conduct heat), A is area, ΔT is the temperature difference and L is thickness. Microscopically, energy is passed from hotter to colder regions by molecular collisions (gases) or free electrons (metals, via the Wiedemann–Franz law k/σ=L₀T, L₀=2.44e-8) or phonons (insulators). Key relations: (1) thermal resistance R=L/(kA), analogous to electrical R=ρL/A, with ΔT=R·(Q/t) (Ohm's-law analogy); (2) heat flux q=Q/A=kΔT/L (heat per unit area); (3) series layers add R=ΣRᵢ, parallel add conductance 1/R=Σ1/Rᵢ — fully analogous to circuits. Conductivity ranges: metals 50–430 (silver 429, copper 400, aluminum 237, iron 80); alloys 10–100; semiconductors 1–100; ceramics/glass 1–2; water 0.6; polymers 0.1–0.5; gases 0.01–0.1 (air 0.026). Applications: (1) building insulation (glass wool, polyurethane); (2) electronics cooling (heatsinks, heat pipes); (3) heat-exchanger design; (4) A/C and fridge insulation; (5) vacuum flasks.

Formula

Fourier's law: Q/t = k·A·ΔT/L

Thermal resistance: R = L/(kA)

Heat flux: q = k·ΔT/L

Ohm analogy: ΔT = R·(Q/t)

Series: R_total = Σ Rᵢ = Σ Lᵢ/(kᵢA)

$$\frac{Q}{t} = \frac{k A \Delta T}{L}, \quad R = \frac{L}{kA}, \quad q = \frac{k\Delta T}{L}, \quad \Delta T = R \cdot \frac{Q}{t}$$

How to Use

  1. Enter conductivity k (W/(m·K); copper 400).
  2. Enter area A (m²), temperature difference ΔT (K) and thickness L (m).
  3. The tool computes heat-transfer rate, thermal resistance and heat flux.

Case Studies

Computer CPU heatsink

CPU 100 W, copper heatsink k=400, A=0.01 m², L=0.01 m, ΔT=50 K → Q=400×0.01×50/0.01=2e4 W, far above need; a fan boosts it further.

Hong Kong's humid summers make PC cooling important; aluminum air coolers are common, water cooling uses copper channels.

Heat pipes exploit phase change (evaporation–condensation) with effective k~10,000 W/m·K, 25× copper — used in laptops and phones.

Building insulation and vacuum flask

Hong Kong summer indoor-outdoor ΔT=10 K. 10 cm glass-wool wall (k=0.04, A=10, L=0.1, ΔT=10) → Q=0.04×10×10/0.1=40 W, saving A/C.

Single glass window (k=1, A=2, L=0.005, ΔT=10) → Q=1×2×10/0.005=4000 W; double-glazed (air gap) drops below 100 W.

Vacuum flask: double silver-coated vacuum wall blocks conduction/convection, silver reflects radiation — keeps drinks hot 24 h.

Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.

Found a problem with the results?

If this calculator's result is wrong, or you have any question about the calculation logic, please let us know. You are viewing:Thermal Conductivity Calculator(/physics/thermal-conductivity)。