Calculatorism

Speed of Sound Calculator

Enter medium bulk modulus and density (or temperature, gas γ, R, M) to compute the speed of sound. Water K=2.2e9, ρ=1000 → c≈1483 m/s; air 20°C → c≈343 m/s.

Input Data

Temperature T (°C). Room 20; 0 ice point; 37 body.
°C
Bulk modulus K (Pa). Water 2.2e9; air 1.42e5; steel 1.6e11.
Pa
Medium density ρ (kg/m³). Water 1000; air 1.225; steel 7800.
kg/m³
Adiabatic index γ. Air 1.4; monatomic 1.67; polyatomic 1.3.
Molar gas constant R=8.314 J/(mol·K).
J/(mol·K)
Molar mass M (kg/mol). Air 0.02897; O₂ 0.032; H₂ 0.002.
kg/mol

Results

Speed of sound c (m/s).
343.42m/s
1,483.239697m/s
343.194034m/s

At a glance:The speed of sound c is the propagation speed of a tiny pressure disturbance in a medium. In any fluid c=√(K/ρ), with K the bulk modulus (Pa, a measure of stiffness) and ρ the density (kg/m³). In an ideal gas, using K=γp and p=ρRT/M, this reduces to c=√(γRT/M)=√(γkT/m), where γ is the adiabatic index, R=8.314 J/(mol·K) the gas constant, T the absolute temperature (K) and M the molar mass (kg/mol). In air, a handy approximation is c≈331.3+0.606·T_C (m/s). Term by term: K (or γ, T) reflects stiffness — a stiffer medium raises c; ρ (or M) reflects inertia — a denser medium lowers c. Physical meaning: sound is faster in stiffer and less dense media. Example: water K=2.2e9 Pa, ρ=1000 → c=√(2.2e9/1000)=√(2.2e6)=1483 m/s; air at 20°C, γ=1.4, M=0.02897 → c=√(1.4×8.314×293.15/0.02897)=√(118183)=343.8 m/s. History: Newton first estimated it, Laplace corrected the adiabatic factor γ in 1816. Applications: (1) sonar and underwater ranging; (2) room and auditorium acoustics; (3) musical instruments (the speed sets pitch with length); (4) medical and industrial ultrasound; (5) atmospheric science; (6) the Mach number (v/c) in aerodynamics.

Formula

General fluid: c = √(K/ρ)

Ideal gas: c = √(γRT/M) = √(γkT/m)

Air approx: c ≈ 331.3 + 0.606·T_C (m/s)

K bulk modulus, ρ density, γ adiabatic index

$$c = \sqrt{\frac{K}{\rho}} = \sqrt{\frac{\gamma R T}{M}} = \sqrt{\frac{\gamma k T}{m}}$$

How to Use

  1. Method 1: enter bulk modulus K and density ρ → c=√(K/ρ).
  2. Method 2: enter temperature T, adiabatic index γ, R and molar mass M → c=√(γRT/M).
  3. Method 2 also gives the air speed c≈331.3+0.606·T_C.

Case Studies

Water, air and temperature

Water K=2.2e9, ρ=1000 → c=1483 m/s (far faster than air).

Air 20°C: c=√(1.4×8.314×293.15/0.02897)=343.8 m/s.

Air: +1°C ≈ +0.6 m/s — temperature strongly sets the speed (wind bands in orchestras tune by temperature).

Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.

Found a problem with the results?

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