Calculatorism

Screw Jack Calculator

Enter load, handle radius, pitch and efficiency to compute effort F=W·p/(2πr·η) and mechanical advantage MA=2πr/p. W=1000 N, r=0.3, p=0.005, η=0.3 → F≈8.84 N, MA≈377.

Input Data

Load W (N). Car 15000; machine 5000; C-clamp 500.
N
Handle radius r (m). Jack 0.2–0.4; C-clamp 0.05.
m
Pitch p (m). M5 thread 0.8 mm; jack 5 mm; worm 1–10 mm.
m
Efficiency η. Triangular thread 0.2–0.4; square 0.3–0.5; ball screw 0.9.

Results

Effort force F (N).
8.841941N
Mechanical advantage MA=2πr/p.
376.991118
Lead p (m).
0.005m

At a glance:A screw is an inclined plane wrapped around a cylinder (the sixth simple machine). The thread cross-section is triangular or square; the pitch p is the distance between adjacent threads (advance per turn). Ideal mechanical advantage MA=2πr/p (r handle radius). Actual effort F=W·p/(2πr·η) (η efficiency; friction increases F). Self-locking: if the thread friction angle exceeds the lead angle, releasing the handle won't let it descend (the jack's safety key). Physical meaning: a screw is an inclined plane of height p and base 2πr, so MA=base/height=2πr/p. Smaller pitch → larger MA (easier) but less advance per turn (slower). Efficiency: triangular thread η=0.2–0.4 (high friction, self-locking); square thread η=0.3–0.5; ball screw η=0.9 (no self-lock, needs a brake). Applications: (1) car jacks; (2) C-clamps and vises (clamping); (3) threaded fasteners (bolts, nuts); (4) wine presses, printing presses; (5) CNC ball screws (precision positioning).

Formula

Mechanical advantage: MA = 2π·r / p

Effort: F = W·p / (2π·r·η)

Lead angle: tanφ = p/(2π·r)

Self-lock: friction angle > lead angle

Energy conservation: F·(2πr) = W·p / η

$$MA = \frac{2\pi r}{p}, \quad F = \frac{W\,p}{2\pi r\,\eta}$$

How to Use

  1. Enter load W (N).
  2. Enter handle radius r (m) and pitch p (m).
  3. Enter efficiency η (triangular 0.3, ball screw 0.9).
  4. The tool gives F=W·p/(2πr·η) and MA.

Case Studies

Car jack and C-clamp

Car jack: W=15000 N, r=0.3, p=0.005, η=0.3 → F=15000×0.005/(2π×0.3×0.3)≈132.6 N, MA=2π×0.3/0.005≈377.

A person pushes 132 N to lift a 15000 N car — the screw amplifies ~113× (η cut it from 377 to ~113 actual).

C-clamp: small r and p gives huge clamping force with little hand torque; triangular thread self-locks so it holds.

Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.

Found a problem with the results?

If this calculator's result is wrong, or you have any question about the calculation logic, please let us know. You are viewing:Screw Jack Calculator(/physics/screw-jack)。