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Raoult's Law Calculator

Enter the solute mole fraction x and the pure-solvent vapor pressure P°; by Raoult's law ΔP = x·P° the tool instantly computes the vapor-pressure lowering and the solution vapor pressure.

Input Data

Solute Mole Fraction
Pure Vapor Pressure
kPa

Results

10kPa
90kPa

At a glance:Raoult's law (proposed by the French chemist François-Marie Raoult in 1887) is a basic law describing the vapor pressure of solutions. It states that for an ideal solution, the vapor pressure P of the solvent above the solution equals the pure-solvent vapor pressure P° times the mole fraction of the solvent x_solvent: P = x_solvent × P°. When you add a 'non-volatile solute' (one that itself produces almost no vapor, like sugar or salt dissolved in water), the solvent mole fraction x_solvent becomes less than 1, so the solution vapor pressure P is necessarily lower than the pure solvent's P° — this phenomenon is called 'vapor-pressure lowering'. Since x_solvent + x_solute = 1, the lowering can be written ΔP = P° − P = P° × (1 − x_solvent) = x_solute × P°. Thus the lowering depends only on the solute mole fraction, not on what the solute is — exactly the hallmark of a 'colligative property'. Using this tool's default: solute mole fraction x_solute = 0.1, pure-solvent vapor pressure P° = 100 kPa, then ΔP = 0.1 × 100 = 10 kPa and the solution vapor pressure P = 100 − 10 = 90 kPa. Microscopically, vapor-pressure lowering happens because solute particles dispersed in the solvent occupy part of the liquid surface and lower the escaping tendency of solvent molecules (lowering the chemical potential), so fewer solvent molecules evaporate per unit time and the equilibrium vapor pressure is lower. Vapor-pressure lowering is the basis for understanding the other two colligative properties: because the vapor pressure is pulled down, the solution must be heated to a higher temperature for its vapor pressure to reach atmospheric pressure, giving 'boiling-point elevation'; similarly the solid–liquid equilibrium temperature is pulled down, giving 'freezing-point depression'. Applications of Raoult's law: first, computing the vapor pressure of solutions with non-volatile solutes (sugar water, salt water). Second, as a criterion for ideal solutions — real solutions that deviate positively or negatively reveal differences in intermolecular forces. Third, determining solute molar mass (back-calculate mole fraction from the lowering, then the molar mass). Fourth, for volatile binary mixtures, each component obeys Raoult's law, allowing computation of total pressure and composition (distillation principle). Notes: first, this formula applies to 'non-volatile solute' ideal dilute solutions; concentrated solutions deviate. Second, use mole fraction, not mass fraction, and x_solute between 0 and 1. Third, P° is the vapor pressure of the pure solvent 'at that temperature'; change temperature, change P°. Fourth, if the solute is an electrolyte, count the total dissociated particles (multiply by the van't Hoff factor).

Formula

Vapor-pressure lowering: ΔP = x_solute × P°.

Solution vapor pressure: P = P° × (1 − x_solute) = x_solvent × P°.

x_solvent + x_solute = 1 (mole fractions sum to 1).

ΔP = P° − P, depends only on solute mole fraction (colligative).

$$\Delta P = x_{\text{solute}} \, P^{\circ}$$

How to Use

  1. Enter the solute mole fraction x (0–1, = moles solute ÷ total moles).
  2. Enter the pure-solvent vapor pressure P° at that temperature (kPa).
  3. The right panel instantly shows the lowering ΔP and the solution vapor pressure P.

Raoult's law vapor-pressure lowering (P° = 100 kPa)

Raoult's law vapor-pressure lowering (P° = 100 kPa)
Solute Mole Fraction xΔP (kPa)Solution P (kPa)
0.05595
0.101090
0.202080
0.303070

For ideal dilute solutions with non-volatile solute; electrolytes must count dissociated total particles.

Case Studies

Vapor-pressure lowering of sugar water

Pure water at some temperature P° = 100 kPa; dissolved sugar gives x_solute = 0.1.

ΔP = 0.1 × 100 = 10 kPa.

Solution vapor pressure P = 100 − 10 = 90 kPa.

Compare lowering by mole fraction

Same solvent (same P°): larger x_solute gives more lowering.

x_solute = 0.05 → ΔP = 5%×P°; x_solute = 0.2 → ΔP = 20%×P°.

The lowering is independent of solute type, depending only on the particle mole fraction.

FAQ

What is Raoult's law?

It states that in an ideal solution the solvent vapor pressure equals the pure-solvent vapor pressure times the solvent mole fraction (P = x_solvent·P°). Adding a non-volatile solute makes x_solvent < 1, so the vapor pressure drops.

Why is vapor-pressure lowering a colligative property?

Because the lowering ΔP = x_solute·P° depends only on the 'amount of solute particles (mole fraction)', not on what the solute is — exactly the definition of a colligative property.

How is the mole fraction computed?

x_solute = moles of solute ÷ (moles of solute + moles of solvent). For an electrolyte solute that dissociates, use the actual total dissociated particle count.

How is vapor-pressure lowering related to boiling-point elevation?

Vapor-pressure lowering is the cause of boiling-point elevation: the lowered vapor pressure must be raised to atmospheric pressure by heating to a higher temperature, so the boiling point rises. Both stem from the solute lowering the solvent's chemical potential.

Do all real solutions obey Raoult's law?

Only ideal dilute solutions strictly obey it. Real concentrated solutions often show positive deviation (weaker forces, higher vapor pressure) or negative deviation (stronger forces, lower vapor pressure); the deviation reflects intermolecular interactions.

Related Tools

References

Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.

Found a problem with the results?

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