Molality Calculator
Enter the solute moles and the solvent mass (kg); using b = n_solute / m_solvent the tool instantly computes the molality (mol/kg) of the solution.
Input Data
Results
At a glance:Molality (symbol b or m, not to be confused with molarity) is an important way to express solution concentration: 'moles of solute per kilogram of solvent': b = moles of solute (mol) / solvent mass (kg), unit mol/kg (colloquially m, e.g. 1 m means 1 mol/kg). Its biggest difference from the more common molarity (c = moles of solute / solution volume, unit mol/L) is the denominator: molality uses the 'mass of solvent', molarity uses the 'volume of solution'. This subtle difference brings a key advantage — molality does not change with temperature. Because mass does not expand or contract with temperature but volume does, chemists always use molality rather than molarity where precision independent of temperature is needed, especially for colligative properties (boiling-point elevation ΔTb = Kb·b, freezing-point depression ΔTf = Kf·b, vapour-pressure lowering). Using this tool's default: dissolve 0.5 mol solute in 0.5 kg solvent (e.g. water), molality b = 0.5 / 0.5 = 1 mol/kg. Moles of solute come from 'mass ÷ molar mass', e.g. 58.5 g NaCl (M = 58.5 g/mol) is 1 mol. Note the denominator is the mass of 'solvent', not 'solution' — solution = solute + solvent; you add a known number of moles of solute to a known mass of pure solvent. For dilute aqueous solutions, since 1 L water weighs about 1 kg and the solution volume is about the solvent volume when the solute is small, molality and molarity are numerically close; but the higher the concentration and the larger the solute molecule, the more they differ. Typical uses of molality: first, colligative-property calculations — adding antifreeze (ethylene glycol) to a car radiator in winter to lower the freezing point, salting roads to melt snow, adding salt in cooking to raise the boiling point; all use molality. Second, osmotic pressure and electrolyte-solution studies. Third, whenever a precise, temperature-independent concentration is needed in physical-chemistry experiments. Notes: first, use the 'solvent' mass in kg (not solution, not g). Second, express the solute as moles; if you have mass, divide by molar mass first. Third, for electrolytes (e.g. NaCl → Na⁺ + Cl⁻) you multiply by the van't Hoff factor i for colligative properties, but the definition of molality itself is unchanged. Fourth, the solvent mass must be positive (≤0 is undefined). In short, this calculator quickly gives molality from solute moles and solvent mass — a practical tool for studying solution properties and colligative phenomena.
Formula
Molality: b = moles of solute n (mol) / solvent mass m (kg).
Unit: mol/kg (written m); denominator is 'solvent' mass, not solution.
Solute moles: n = mass (g) ÷ molar mass (g/mol).
Advantage: temperature-independent; used in ΔTb = Kb·b, ΔTf = Kf·b.
$$b = \dfrac{n_{\text{solute}}}{m_{\text{solvent}}\,(\text{kg})}$$How to Use
- Enter the solute moles n (mol); obtain from mass ÷ molar mass.
- Enter the solvent (e.g. water) mass m (kg).
- The right panel instantly shows the molality b (mol/kg).
Molality vs solute moles (solvent fixed at 1 kg)
| Solute Moles n (mol) | Solvent Mass m (kg) | Molality b (mol/kg) | Note |
|---|---|---|---|
| 0.5 | 1 | 0.5 | half molal |
| 1 | 1 | 1 | 1 molal |
| 2 | 1 | 2 | 2 molal |
| 1 | 2 | 0.5 | double solvent halves concentration |
Molality is based on solvent mass and does not change with temperature.
Case Studies
Basic molality calculation
Dissolve 0.5 mol glucose in 0.5 kg water; find the molality.
b = n / m = 0.5 / 0.5 = 1 mol/kg.
This is a 1 molal (1 m) solution.
Convert mass to moles then find molality
Dissolve 117 g NaCl (M = 58.5 g/mol) in 2 kg water.
Solute moles n = 117 / 58.5 = 2 mol.
b = 2 / 2 = 1 mol/kg; emphasises solvent mass as denominator and converting mass to moles first.
FAQ
What is the difference between molality and molarity?
Molality b = moles solute / solvent mass (kg), unit mol/kg; molarity c = moles solute / solution volume (L), unit mol/L. The former uses mass as denominator and is temperature-independent; the latter uses volume, which changes with temperature due to thermal expansion.
Why use molality for colligative properties?
Because colligative-property formulas (ΔTb = Kb·b, ΔTf = Kf·b) are based on a temperature-independent concentration, and molality is based on mass and does not change with temperature — the most suitable for such calculations.
Is the denominator solvent or solution mass?
It is the 'solvent' mass. Solution = solute + solvent; molality uses only the pure solvent (e.g. water) mass as denominator, not including the solute mass.
I only have mass, not moles of solute. What to do?
First convert: moles = mass (g) ÷ molar mass (g/mol). E.g. 58.5 g NaCl (M = 58.5) is 1 mol, then substitute into b = n / m.
Why are molality and molarity close for dilute aqueous solutions?
Because 1 L water weighs about 1 kg, and at low solute the solution volume is about the solvent volume, so the denominators are numerically close. But the higher the concentration and the larger the solute, the more they differ.
Related Tools
References
Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.