Calculatorism

Water Hammer Calculator

Enter fluid density, pressure-wave speed and velocity change to compute the water-hammer pressure rise Δp=ρaΔv and head Δh. ρ=1000, a=1200, Δv=2 → Δp=2.4 MPa (~245 m head).

Input Data

Fluid density (kg/m³); clean water ~1000.
kg/m³
Pressure-wave speed a (m/s); rigid pipe ~1000–1400.
m/s
Velocity change Δv before/after valve action (m/s).
m/s

Results

Pressure rise Δp (Pa).
2,400,000Pa
Pressure head Δh (m of water).
244.6483m

At a glance:Water hammer is the instantaneous pressure shock produced when a liquid flowing in a pipe changes velocity abruptly (typically a valve closing suddenly or a pump tripping) — the flow is forced to stop, its kinetic energy converts to pressure, which travels back and forth along the pipe as a pressure wave, often with a banging noise (hence 'water hammer'). This transient high pressure can far exceed normal working pressure and rupture pipes, joints or equipment — a key hazard in pipeline design. The Joukowsky equation gives the maximum surge for an instantaneous closure: Δp=ρ·a·Δv, where Δp is the pressure rise (Pa), ρ the fluid density (kg/m³), a the pressure-wave speed in the pipe (m/s) and Δv the velocity change (m/s). In head units (metres of water): Δh=Δp/(ρg), g=9.81. Details: ρ is fluid density, clean water ~1000 kg/m³. a is the pressure-wave speed (close to sound speed), depending on fluid bulk modulus and pipe/wall elasticity — ~1000–1400 m/s in rigid metal pipe, lower in elastic plastic. Δv is the velocity difference before/after closure; for a full close it equals the original velocity v. 'Instantaneous closure' means closure time shorter than the wave round-trip time (2L/a, L pipe length); then Δp reaches maximum. A slower closure reduces Δp proportionally. Example: ρ=1000, a=1200 m/s, Δv=2 m/s → Δp=1000×1200×2=2,400,000 Pa=2.4 MPa, head Δh=2.4e6/(1000×9.81)≈244.6 m. That is, slamming this valve raises the pressure by the equivalent of 244 m of water — a huge threat to irrigation/supply pipes whose normal pressure is only tens of metres. Uses: (1) assess surge risk from valve slam or pump trip; (2) design minimum safe closure time (slow down to lower pressure); (3) configure protection — air valves, surge towers, surge tanks, check valves; (4) choose pipe material and wall thickness for transient pressure. Notes: (1) this formula gives the maximum rise for instantaneous closure; slow closure needs transient analysis (method of characteristics); (2) set a correctly from fluid and pipe elasticity, or you underestimate risk; (3) it is the pressure rise — add the static pressure before closure for total; (4) keep SI units (ρ kg/m³, a and Δv m/s). In short, water-hammer rise is estimated by the Joukowsky equation Δp=ρaΔv, the basis of pipeline surge protection design.

Formula

Joukowsky: Δp = ρ·a·Δv (Pa)

Head rise: Δh = Δp/(ρ·g), g=9.81

Valid for instantaneous closure (closure time < 2L/a); slow closure reduces Δp proportionally

$$\Delta p = \rho\,a\,\Delta v,\quad \Delta h = \dfrac{\Delta p}{\rho g}$$

How to Use

  1. Enter fluid density ρ (water 1000) and wave speed a (rigid pipe ~1200 m/s).
  2. Enter velocity change Δv (full closure = original velocity).
  3. The tool computes Δp=ρaΔv and the head rise Δh.

Case Studies

Surge from slamming an irrigation valve

Irrigation main, v=2 m/s, valve shuts instantly, Δv=2 m/s; ρ=1000, a=1200 m/s.

Δp=1000×1200×2=2.4 MPa, head Δh≈244.6 m.

This transient far exceeds normal pressure; slow the closure or add air valves/surge protection.

Lower velocity eases water hammer

Reduce design velocity from 2 to 1 m/s (Δv=1).

Δp=1000×1200×1=1.2 MPa, head Δh≈122.3 m — half.

Pressure rise is proportional to velocity; a larger pipe diameter lowers velocity and the hammer risk.

Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.

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