Stefan-Boltzmann Law Calculator
Enter emissivity ε, area A and absolute temperature T to compute radiated power P=ε·σ·A·T⁴. ε=0.9, A=1 m², T=300 K → P≈413 W. T in Kelvin.
Input Data
Results
At a glance:The Stefan-Boltzmann law (Josef Stefan 1879, Ludwig Boltzmann 1884) describes the power a body radiates due to its temperature. For a grey surface: P=ε·σ·A·T⁴, where P is radiated power (W), ε is emissivity (0 to 1, dimensionless), σ is the Stefan-Boltzmann constant =5.670374419×10⁻⁸ W/(m²·K⁴), A is the radiating area (m²) and T is the absolute temperature (K — must be Kelvin). This law's most important feature is that radiated power is proportional to the fourth power of absolute temperature: a small temperature rise sharply increases radiation — double T and radiation becomes 16× larger. Emissivity ε describes how much a real surface radiates relative to an ideal blackbody: blackbody ε=1 (strongest), leaves/soil/water are near 0.9–0.98, polished metals as low as 0.05 (barely radiate). Example: ε=0.9, A=1 m², T=300 K (≈27°C) → P=0.9×5.670e-8×1×300⁴ ≈ 413.37 W, radiating about 413 J per second. At T=500 K (blackbody ε=1): P≈3543.75 W — the fourth-power effect makes radiation surge. The actual net exchange must consider ambient T_env: P_net=εσA(T⁴−T_env⁴). Uses: (1) long-wave crop canopy radiation and night radiative cooling (frost warning); (2) Earth energy balance and greenhouse effect, planetary equilibrium temperature; (3) heatsink, solar-collector and insulation radiation loss; (4) infrared thermometry (infer temperature from radiation). Notes: (1) T must be absolute K (°C+273.15), Celsius badly breaks it; (2) ε depends on material and surface, range 0–1; (3) this tool gives emitted power — net exchange subtracts εσA·T_env⁴; (4) keep SI units consistent. In short, thermal radiation power is given by P=εσA·T⁴; the fourth-power law is the core of thermal radiation, energy balance and radiative cooling.
Formula
Stefan-Boltzmann: P = ε·σ·A·T⁴, σ=5.670374419×10⁻⁸ W/(m²·K⁴)
ε emissivity (0–1), A area (m²), T absolute (K); P power (W)
Net exchange: P_net = ε·σ·A·(T⁴ − T_env⁴)
$$P = \varepsilon\,\sigma\,A\,T^4$$How to Use
- Enter emissivity ε (leaf ~0.95, blackbody 1) and area A.
- Enter absolute temperature T (remember °C + 273.15 = K).
- The tool computes the radiated thermal power P=εσA·T⁴.
Case Studies
Crop leaf long-wave radiation
Hong Kong night leaf ~27°C (T=300 K), ε≈0.9, A=1 m².
P = 0.9×5.670e-8×1×300⁴ ≈ 413.37 W/m².
After subtracting sky back-radiation it is net radiative cooling — a clear night drops leaf temp below dew point, causing frost; the basis of frost warning.
Effect of temperature rise on radiation
Same blackbody (ε=1, A=1 m²) from 300 K to 500 K.
P_300≈459 W; P_500≈3544 W.
Temp ×1.67, radiation ×7.7 (500⁴/300⁴) — high-T objects radiate strongly.
Content review: Calculatorism Editorial Team. Results are for reference only; please refer to the relevant authorities for the official figures.