Rotational Kinetic Energy Calculator
Enter moment of inertia I and angular velocity ω to compute rotational kinetic energy E=½Iω². I=2 kg·m², ω=3 rad/s → E=9 J; double ω → 4× energy.
Input Data
Results
At a glance:Rotational kinetic energy (E or K_rot) is the energy a body has because it is spinning — the rotational version of kinetic energy. Just as a linearly moving object has translational KE E=½mv² (m mass, v speed), a body rotating about an axis has energy because every particle is moving; that is rotational KE. The formula is E=½·I·ω², where I is the moment of inertia (the rotational 'mass', kg·m²) and ω is the angular velocity (rad/s); E is in joules. The form exactly mirrors translational KE ½mv²: mass m is replaced by moment of inertia I, linear speed v by angular speed ω. Example (default): I=2 kg·m², ω=3 rad/s → E=½×2×3²=½×2×9=9 J. Two key points: (1) energy scales with the square of ω — double the angular speed and energy becomes 4×, so a fast spinner stores a lot; (2) it scales with I — mass placed farther out (larger I) stores more energy at the same ω. For an object that both translates and rotates (a rolling ball or wheel), total KE is the sum: E_total=½mv² (translation) + ½Iω² (rotation). Applications: (1) flywheel energy storage — a large-I rotor at high ω stores energy as rotational KE, used to smooth engine output, power presses, and even grid frequency regulation and regenerative braking; (2) power generation — hydro, steam and wind turbines convert rotational KE to electricity; (3) sports — gymnastics, skating, hammer throw; (4) rolling-object mechanics — a ball rolling down a slope splits gravitational PE into translation and rotation, so it is slower than pure sliding; (5) astrophysics — the huge spin energy of stars and planets. Notes: (1) use the I for the correct shape and axis (point mass mr², disc ½mr²); (2) ω must be in rad/s (1 rev = 2π rad; convert rpm first); (3) for combined motion add translational KE; (4) the calculator takes a non-negative I, and ω² makes either sign give the same energy.
Formula
Rotational KE: E = ½·I·ω² (J)
Matches translational: E = ½mv² (I↔m, ω↔v)
Rolling total: E = ½mv² + ½Iω²
Energy scales with ω²
$$E = \tfrac{1}{2} I \omega^2$$How to Use
- Enter the moment of inertia I about the axis (kg·m²).
- Enter the angular velocity ω (rad/s).
- The tool shows rotational KE E (J).
Case Studies
Basic rotational KE
I=2 kg·m², ω=3 rad/s.
E = ½×2×3² = 9 J.
Double ω → 4× energy
Same I=2 kg·m², ω=6 rad/s.
E = ½×2×6² = 36 J.
Doubling ω quadruples the energy (square law).
Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.