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Resistor Combination Calculator

Combine 1–3 resistors in series or parallel. Series: R=R1+R2+... Parallel: 1/R=1/R1+1/R2+.... 100Ω+200Ω series=300Ω, parallel≈66.7Ω.

Input Data

Series adds resistances; parallel uses the reciprocal rule.
First resistor value (Ω).
Second resistor value (Ω); leave 0 to ignore.
Third resistor value (Ω); leave 0 to ignore.

Results

300
串聯總電阻 = 300 Ω。

At a glance:Resistors in series add: R=R₁+R₂+… . Resistors in parallel follow the reciprocal rule: 1/R=1/R₁+1/R₂+… (equivalently R=R₁R₂/(R₁+R₂) for two). Properties: (1) series raises the total resistance; (2) parallel lowers it below the smallest value; (3) equal parallel resistors halve the value (two) or divide by n. Applications: (1) making non-standard resistance values; (2) LED current limiting; (3) sensor voltage dividers; (4) gain-setting in op-amp circuits; (5) load sharing.

Formula

Series: R = R₁+R₂+R₃+…

Parallel: 1/R = 1/R₁+1/R₂+1/R₃+…

Two in parallel: R = R₁R₂/(R₁+R₂)

$$R_{s} = \sum R_i, \quad \frac{1}{R_{p}} = \sum \frac{1}{R_i}$$

How to Use

  1. Pick series or parallel mode.
  2. Enter up to three resistor values (R₃ optional).
  3. The equivalent resistance is shown instantly.

Case Studies

LED current-limiting resistor

An LED drops ~2 V and needs 20 mA from a 5 V supply. Series resistor R=(5−2)/0.02=150 Ω.

Use 150 Ω or the nearest standard 160 Ω; power rating ≥0.06 W, so 1/4 W is safe.

Two 150 Ω in series give 300 Ω and halve the current — useful if a single value is unavailable.

Content review: Calculatorism Science Team. Results are for reference only; please refer to the relevant authorities for the official figures.

Found a problem with the results?

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